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Wednesday 29 January 2020
sum of natural numbers using loop
Source Code:
#include<iostream>
using namespace std;
int main()
{
int i,s,n;
cout<<"Enter one integer: ";
cin>>n;
for(i=1;i<=n;i++)
{
s=n*(n+1)/2;
}
cout<<s;
return 0;
}
Program Output:
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